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make faster and explicit way for plotting?...

Asked by: SSMB 100
performance explore numeric
March 08 2025
4  2

this function i have is so long and my parameter are twenty they are two much when i make a change in explore i the change is so slow and i can't see some of this parameter how act to figure when i change becuase the placement of parameters i want some of parameter being in right  and some of them being in right  and figure be in the middle for see them together can we do something like that?

figure.mw

Is LieAlgebras[Cohomology] broken in Maple 2024.2?...

Asked by: Massimo Bertolotti 5
liealgebra cohomology
March 07 2025
1  0

Hi everyone,

I'm trying to compute the cohomology group of some Lie algebras using the LieAlgebra package, but it appears that the Cohomology command doesn't provide the correct basis for the higher dimensional cohomology group, instead repeating up to the correct dimension only one element.

For example, with the following Lie algebra

L1:=_DG([["LieAlgebra", Alg1, [6]], [[[1, 3, 2], 1], [[1, 2, 3], -1], [[4, 6, 5], 1], [[4, 5, 6], -1]]])
DGSetup(L1)

the command

C := RelativeChains([])

does provide the correct k-forms on Alg1, but then

H := Cohomology(C)
provides
[[theta4,theta1],[theta1 &w theta4, theta1 &w theta4, theta1 &w theta4],[theta1 &w theta2 &w theta3,theta1 &w theta2 &w theta3,theta1 &w theta2 &w theta3,theta1 &w theta2 &w theta3], [theta1 &w theta2 &w theta3 &w theta4,theta1 &w theta2 &w theta3 &w theta4,theta1 &w theta2 &w theta3 &w theta4],[theta1 &w theta2 &w theta3 &w theta4 &w theta5 &w theta6, theta1 &w theta2 &w theta3 &w theta4 &w theta5 &w theta6], [theta1 &w theta2 &w theta3 &w theta4 &w theta5 &w theta6]

A similar thing does happen for the examples provided in the online help (e.g. example 1 from https://de.maplesoft.com/support/help/Maple/view.aspx?path=DifferentialGeometry/LieAlgebras/Cohomology). Is the command broken?

Any help is really appreciated.

what is problem why i can't get result?...

Asked by: salim-barzani 1555
substitution pde differential-equations
March 05 2025
3  2
> 

restart
> 

with(PDEtools)
> 

undeclare(prime, quiet); declare(u(x, y, z, t), quiet); declare(f(x, y, z, t), quiet)

``

 (1)
> 

thetai := k[i]*(t*w[i]+y*l[i]+z*r[i]+x)
> 

eqw := w[i] = (-1+sqrt(-4*beta*mu*l[i]-4*delta*mu*r[i]-4*mu*k[i]^2-4*alpha*mu+1))/(2*mu)
> 

Bij := proc (i, j) options operator, arrow; -24*mu/(sqrt(1+(-4*beta*l[j]-4*delta*r[j]-4*alpha)*mu)*sqrt(1+(-4*beta*l[i]-4*delta*r[i]-4*alpha)*mu)-1+((2*r[i]+2*r[j])*delta+(2*l[i]+2*l[j])*beta+4*alpha)*mu) end proc
> 

NULL
> 

theta1 := normal(eval(eval(thetai, eqw), i = 1)); theta2 := normal(eval(eval(thetai, eqw), i = 2))
> 

eqf := f(x, y, z, t) = theta1*theta2+Bij(1, 2)
> 

eqfcomplex := collect(evalc(eval(eval(eqf, l[2] = conjugate(l[1])), l[1] = a+I*b)), t)
> 

eq17 := u(x, y, z, t) = 2*(diff(diff(f(x, y, z, t), x), x))/f(x, y, z, t)-2*(diff(f(x, y, z, t), x))^2/f(x, y, z, t)^2; equ := simplify(eval(eq17, eqfcomplex))

So we want to find a substitution that removes the time dependence from u. One way is to find the maximum and see how it moves. Here, the first solution gives what we want.

> 

ans := solve({diff(rhs(equ), x), diff(rhs(equ), y), diff(rhs(equ), z)}, {x, y, z}, explicit)
 

NULL

Download hfz.mw

There is any way for see the outcome of result? fo...

Asked by: salim-barzani 1555
explore substitution plotting
March 05 2025
3  0

i need the result for (eqt33) but i can reach the result there is any  other way for finding? i need to plot 3D of that function but without have the function how i can do explore on it

w1.mw

How to `Describe` “Iterator:-Product”? ...

Asked by: sursumCorda 1239
March 03 2025
2  2

I would like to generate a brief description of the object Iterator:-Product but I get the following error:  

Describe(Iterator:-Product);

object Product :: Class<<36893490916968945900>>:

    ModuleApply( )

    ModuleCopy( self::_Product, proto::_Product, 
Error, (in Describe) `proto` does not evaluate to a module

How do I get rid of this message? 

How find parameter in this equation ?...

Asked by: Arya-S-AA 175
parameters substitution pde
March 02 2025
4  0

i did try but i don't know the result is not come out? also i am not sure to put equation in eq1 in pde or linear part?

> 

restart
> 

with(PDEtools)
> 

with(LinearAlgebra)
> 

NULL
> 

with(SolveTools)
> 

undeclare(prime)

`There is no more prime differentiation variable; all derivatives will be displayed as indexed functions`

 (1)
> 

declare(u(x, y, t))

u(x, y, t)*`will now be displayed as`*u

 (2)
> 

declare(f(x, y, t))

f(x, y, t)*`will now be displayed as`*f

 (3)
> 

pde := diff(u(x, y, t), t, y)+diff(u(x, y, t), `$`(x, 3), y)-3*(diff(u(x, y, t), x))*(diff(u(x, y, t), x, y))-3*(diff(u(x, y, t), `$`(x, 2)))*(diff(u(x, y, t), y))+alpha*(diff(u(x, y, t), x, y))+beta*(diff(u(x, y, t), `$`(x, 2)))

diff(diff(u(x, y, t), t), y)+diff(diff(diff(diff(u(x, y, t), x), x), x), y)-3*(diff(u(x, y, t), x))*(diff(diff(u(x, y, t), x), y))-3*(diff(diff(u(x, y, t), x), x))*(diff(u(x, y, t), y))+alpha*(diff(diff(u(x, y, t), x), y))+beta*(diff(diff(u(x, y, t), x), x))

 (4)
> 

pde_nonlinear, pde_linear := selectremove(proc (term) options operator, arrow; has((eval(term, u(x, y, t) = a*u(x, y, t)))/a, a) end proc, pde)

-3*(diff(u(x, y, t), x))*(diff(diff(u(x, y, t), x), y))-3*(diff(diff(u(x, y, t), x), x))*(diff(u(x, y, t), y)), diff(diff(u(x, y, t), t), y)+diff(diff(diff(diff(u(x, y, t), x), x), x), y)+alpha*(diff(diff(u(x, y, t), x), y))+beta*(diff(diff(u(x, y, t), x), x))

 (5)
> 

eq := u(x, y, t) = -2*(diff(ln(f(x, y, t)), x))

u(x, y, t) = -2*(diff(f(x, y, t), x))/f(x, y, t)

 (6)
> 

eq1 := -(1/2)*numer(normal(eval(pde_linear, eq)))

f(x, y, t)^4*(diff(diff(diff(f(x, y, t), x), x), x))*beta+f(x, y, t)^4*(diff(diff(diff(f(x, y, t), x), x), y))*alpha-f(x, y, t)^3*(diff(f(x, y, t), y))*(diff(diff(f(x, y, t), x), x))*alpha-2*f(x, y, t)^3*(diff(diff(f(x, y, t), x), y))*(diff(f(x, y, t), x))*alpha-3*f(x, y, t)^3*(diff(f(x, y, t), x))*(diff(diff(f(x, y, t), x), x))*beta+2*f(x, y, t)^2*(diff(f(x, y, t), y))*(diff(f(x, y, t), x))^2*alpha+2*f(x, y, t)^2*(diff(f(x, y, t), x))^3*beta+(diff(diff(diff(f(x, y, t), t), x), y))*f(x, y, t)^4+(diff(diff(diff(diff(diff(f(x, y, t), x), x), x), x), y))*f(x, y, t)^4-(diff(diff(f(x, y, t), t), x))*(diff(f(x, y, t), y))*f(x, y, t)^3-(diff(diff(diff(diff(f(x, y, t), x), x), x), x))*(diff(f(x, y, t), y))*f(x, y, t)^3-(diff(diff(f(x, y, t), x), y))*(diff(f(x, y, t), t))*f(x, y, t)^3-4*(diff(diff(diff(f(x, y, t), x), x), x))*(diff(diff(f(x, y, t), x), y))*f(x, y, t)^3-(diff(f(x, y, t), x))*(diff(diff(f(x, y, t), t), y))*f(x, y, t)^3-4*(diff(diff(diff(diff(f(x, y, t), x), x), x), y))*(diff(f(x, y, t), x))*f(x, y, t)^3-6*(diff(diff(f(x, y, t), x), x))*(diff(diff(diff(f(x, y, t), x), x), y))*f(x, y, t)^3+2*(diff(f(x, y, t), x))*(diff(f(x, y, t), t))*(diff(f(x, y, t), y))*f(x, y, t)^2+8*(diff(diff(diff(f(x, y, t), x), x), x))*(diff(f(x, y, t), x))*(diff(f(x, y, t), y))*f(x, y, t)^2+6*(diff(diff(f(x, y, t), x), x))^2*(diff(f(x, y, t), y))*f(x, y, t)^2+24*(diff(diff(f(x, y, t), x), x))*(diff(f(x, y, t), x))*(diff(diff(f(x, y, t), x), y))*f(x, y, t)^2+12*(diff(diff(diff(f(x, y, t), x), x), y))*(diff(f(x, y, t), x))^2*f(x, y, t)^2-36*(diff(diff(f(x, y, t), x), x))*(diff(f(x, y, t), x))^2*(diff(f(x, y, t), y))*f(x, y, t)-24*(diff(f(x, y, t), x))^3*(diff(diff(f(x, y, t), x), y))*f(x, y, t)+24*(diff(f(x, y, t), x))^4*(diff(f(x, y, t), y))

 (7)
> 

NULL
> 

T := f(x, y, t) = h*a[10]+m^2+n^2+a[9]
> 

T1 := m = t*a[3]+x*a[1]+y*a[2]+a[4]
> 

T2 := n = t*a[7]+x*a[5]+y*a[6]+a[8]
> 

T3 := h = a[10]*exp(t*p[3]+x*p[1]+y*p[2])
> 

L2 := expand(subs({T1, T2, T3}, T))

f(x, y, t) = a[10]^2*exp(p[3]*t)*exp(p[1]*x)*exp(p[2]*y)+t^2*a[3]^2+2*t*x*a[1]*a[3]+2*t*y*a[2]*a[3]+x^2*a[1]^2+2*x*y*a[1]*a[2]+y^2*a[2]^2+2*t*a[3]*a[4]+2*x*a[1]*a[4]+2*y*a[2]*a[4]+a[4]^2+t^2*a[7]^2+2*t*x*a[5]*a[7]+2*t*y*a[6]*a[7]+x^2*a[5]^2+2*x*y*a[5]*a[6]+y^2*a[6]^2+2*t*a[7]*a[8]+2*x*a[5]*a[8]+2*y*a[6]*a[8]+a[8]^2+a[9]

 (8)
> 

eq9a := eval(eq1, L2)
> 

indets(%)

{alpha, beta, t, x, y, a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], a[9], a[10], p[1], p[2], p[3], exp(p[1]*x), exp(p[2]*y), exp(p[3]*t)}

 (9)
> 

p2b := subs({exp(p[1]*x) = eX, exp(p[2]*y) = eY, exp(p[3]*t) = eT}, eq9a); indets(%)

{alpha, beta, eT, eX, eY, t, x, y, a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], a[9], a[10], p[1], p[2], p[3]}

 (10)
> 

p2c := numer(normal(p2b))
> 

eqns := {coeffs(collect(p2c, {eT, eX, eY}, distributed), {eT, eX, eY})}; nops(%)

5

 (11)
> 

solve(eqns, {a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], a[9], a[10], p[1], p[2], p[3]})
 

NULL

Download parameters.mw

Why is this type assertion not invalid?...

Asked by: sursumCorda 1239
March 01 2025
1  6

If I understand right, in the following calling an exception should be raised since the return value of the matching coercion procedure is of course not of type “set”: 

restart;
foo := (x::coerce(set, (y::rtable) -> convert(y, list))) -> x:
foo(<0>);
 = 
                              [0]

Did I miss something?

How define the PDE which contain integral with i...

Asked by: salim-barzani 1555
pde differential-equations duplicate-question
February 21 2025
1  10

i try find some part of solution of this kind of pde but i can't get results my openion is maybe this pde is wronge when i defined 

pde.mw

Symbolic computation in General Relativity with en...

Asked by: MIKE_690 0
physics tensor energy
February 18 2025
0  2

 Can I solve the Tolman-Oppenheimer-Volkoff equation with Maple ?  I'm having trouble with Einstein's equation with the energy tensor as the second member

How by apply limit remove the constant with diff...

Asked by: salim-barzani 1555
limit duplicate-question
February 16 2025
2  5

How apply long wave limit for removing the constant k in such function , i need a general formula 

Limiting process from eq 12 to Bij

> 

restart
> 

NULL

Eq 12.

> 

eij := ((-3*k[i]*(k[i]-k[j])*l[j]+beta)*l[i]^2-(2*(-3*k[j]*(k[i]-k[j])*l[j]*(1/2)+beta))*l[j]*l[i]+beta*l[j]^2)/((-3*k[i]*(k[i]+k[j])*l[j]+beta)*l[i]^2-(2*(3*k[j]*(k[i]+k[j])*l[j]*(1/2)+beta))*l[j]*l[i]+beta*l[j]^2)

((-3*k[i]*(k[i]-k[j])*l[j]+beta)*l[i]^2-2*(-(3/2)*k[j]*(k[i]-k[j])*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)/((-3*k[i]*(k[i]+k[j])*l[j]+beta)*l[i]^2-2*((3/2)*k[j]*(k[i]+k[j])*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)

 (1)
> 

eval(eij, k[j] = k[i]); series(%, k[i], 3); convert(%, polynom); eval(%, k[j] = k[i]); Bij := %

(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)/((-6*k[i]^2*l[j]+beta)*l[i]^2-2*(3*k[i]^2*l[j]+beta)*l[j]*l[i]+beta*l[j]^2)

  

series(1+((6*l[i]^2*l[j]+6*l[i]*l[j]^2)/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2))*k[i]^2+O(k[i]^4),k[i],4)

  

1+(6*l[i]^2*l[j]+6*l[i]*l[j]^2)*k[i]^2/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)

  

1+(6*l[i]^2*l[j]+6*l[i]*l[j]^2)*k[i]^2/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)

  

1+(6*l[i]^2*l[j]+6*l[i]*l[j]^2)*k[i]^2/(beta*l[i]^2-2*beta*l[i]*l[j]+beta*l[j]^2)

 (2)
> 

NULL

NULL

Download b12.mw

What is Idea behind finding parameter?...

Asked by: salim-barzani 1555
parameters exponential pde
February 15 2025
1  10

I need to find parameter a[12] any one have any vision for finding parameter  , in p2a must contain 3 exponential but we recieve 19 of them which is something i think it is trail function but trail is give me result so must be a way for finding parameter 

a[12]-pde.mw

How can check pdetest when function is not short? ...

Asked by: salim-barzani 1555
explore pde differential-equations
February 14 2025
1  4

the function is true but i want to be sure when i use pdetest must give me zero, but there must be a way for checking such function, please if your pc not strong don't click the command pdetest, i want use explore for such function but i am not sure it work or not, becuase the graph are a little bit strange  and long , i want  a way for easy plotting and visualization of such graph , can anyone help for solve this issue?

 sol.mw

How do convert language to Matlab when expression...

Asked by: salim-barzani 1555
codegeneration matlab
February 13 2025
0  0

i don't know how apply conversation language to matlab in righ hand side  don't show up to do conversation language for short is come up but for this not 

> 

restart
> 

K := (2*(k[1]*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1])+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*(k[1]+k[2])*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])/((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)+k[2]*exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])+((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*(k[2]+k[3])*exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[2]-p[3])^2*alpha-(k[2]+k[3])^2)+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*(k[1]+k[2]+k[3])*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/(((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]+k[3])^2))+((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*(k[1]+k[3])*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)+k[3]*exp((3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])))/(1+exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1])+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])/((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)+exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])+((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[2]-p[3])^2*alpha-(k[2]+k[3])^2)+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/(((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]+k[3])^2))+((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)+exp((3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3]))

2*(k[1]*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1])+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*(k[1]+k[2])*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])/((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)+k[2]*exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])+((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*(k[2]+k[3])*exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[2]-p[3])^2*alpha-(k[2]+k[3])^2)+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*(k[1]+k[2]+k[3])*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/(((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]+k[3])^2))+((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*(k[1]+k[3])*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)+k[3]*exp((3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3]))/(1+exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1])+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])/((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)+exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2])+((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*exp((3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[2]-p[3])^2*alpha-(k[2]+k[3])^2)+((p[1]-p[2])^2*alpha-(k[1]-k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]-k[3])^2)*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[2]*t*alpha*p[2]^2+(1/4)*t*k[2]^3+k[2]*p[2]*y+k[2]*x+k[2]*z+eta[2]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/(((p[1]-p[2])^2*alpha-(k[1]+k[2])^2)*((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)*((p[2]-p[3])^2*alpha-(k[2]+k[3])^2))+((p[1]-p[3])^2*alpha-(k[1]-k[3])^2)*exp((3/4)*k[1]*t*alpha*p[1]^2+(1/4)*t*k[1]^3+k[1]*p[1]*y+k[1]*x+k[1]*z+eta[1]+(3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3])/((p[1]-p[3])^2*alpha-(k[1]+k[3])^2)+exp((3/4)*k[3]*t*alpha*p[3]^2+(1/4)*t*k[3]^3+k[3]*p[3]*y+k[3]*x+k[3]*z+eta[3]))

 (1)
 

NULL

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Missing "Convert Output Units:" in the context pan...

Asked by: Daniel SC 10
windows units context-panel
February 11 2025
2  2

Hello,

I have updated to maple 2024 on both my desktop and my laptop, and now I am missing the feature "Convert Output Units:" in the context tab on my windows 11 laptop. It's still available on my windows 10 desktop.

I have tried reinstalling maple and installing java, but it unfortunately did not help. Due to limited school licences, I am unable to test with maple 2023.

Is this an issue you have heard of?

Thank you in advance,

Daniel

 

And here is the context menu on windows 11. Also nothing happens when I click "Format -> Convert Output Units" in the top menu. 

 

Why is maple not able to export pdf with high qual...

Asked by: danilkp1234 10
pdf export
February 11 2025
2  2

Hello, i have been drawing some cool 3d plots for my assignment, but when i use the export button and export it as pdf the plots turn out very low quality. 

See the image below is using the export function

Then i tried something different i tried using the print button and printing to a pdf.

That resulted in a different looking plot

This plot using the print to pdf feature looks much nicer, but the 3d text plot has become impossible to read.

 

Is there a way to fix that? Or to make the export to pdf feature export at higher quality? 

Best Regards

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