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I'm working with some rather complicated sums involving absolute value, I'd like convert the sum into a piecewise defined function. For example

Greetingsi

Maple does not simplify the expression -2*Pi*sin(Pi*a)/(-1+cos(2*Pi*a)). How can I make it do so? 

Thanks,

Maple 15 64-bit on Windows 7

I have to generate F(x) of a function with a degree of 5 who has zeros of x=2,x=1+3i,x=2-4i

After i put it into maple i use the command expand to give me the total function but afterwards i get this 144*i^4*x-25*i^2*x^3+x^5-288*i^4+118*i^2*x^2-8*x^4-188*i^2*x+25*x^3+104*i^2-38*x^2+28*x-8

i need to know what command can i use to get it to converts i^4 to 1 and i^2 to-1 that way i can truly simplify it. 

I've the equation

(-x^2+eta^2+2*x*xi+2*x*eta-xi^2-2*xi*eta-2*x*y-2*y*eta+2*xi*y+y^2)*(-x^2-2*x*eta+eta^2+2*x*xi+2*xi*eta-xi^2+2*x*y-2*xi*y-2*y*eta+y^2)-(x-xi)^4+6*((x-xi)^2)(-y+eta)^2-(-y+eta)^4

The answer is 0

But I can't get the answer by simplify and expand

Then which .Thanks

for example:

>>simplify(cos(i)*sin(u)/sin(i),trig)

                    cos(i)*sin(u)/sin(i)

Maple do'not  simplify cos(i)/sin(i)=ctan(i) atomaticly.

also  half angle formulas:

>>simplify(sin(i)/(cos(i)+1),trig)

           sin(i)/(cos(i)+1)

i want to get tan(i/f)

I would like to simplify algebraic modulo expression.

For example, (N+k) mod N should be simplified to k mod N (N and k are positive integers).

Is there a way to achieve this with maple?

Thank you!

As an intermediate result in a longer calculation I got the following equation:

Isolating p, Maple delivers

Calculated manually,...

Hey guys !

I wondered if it's possible in maple to hundle functions, for exemple to know if a function is a sum or a product of two functions.

Is there a function like this : sum (\x -> x+3)  -------->  [(\x -> x), \x -> 3] ?

If I ask this, is because I want to know if it's possible de rewrite the function `deriv` or `integrate` or `simplify` by hands, without using the native functions.

simplify(sqrt(a+sqrt(b))*sqrt(a-sqrt(b))-sqrt((a+sqrt(b))*(a-sqrt(b)))) assuming a>0,b>0,a>sqrt(b);

It's mathematically zero but it does not return zero.

How can I simplify it?

I want to get the zeroth order and first order perturbation equations of the following nonlinear coupled ODE.

restart; N := 1

alias(eta = e, theta = t)

eq[1] := 5*(diff(F(e), `$`(e, 3)))+(1+3/m)*F(e)*(diff(F(e), `$`(e, 2)))-(2+1/m)*(diff(F(e), e))^2-(4+2/m)*H(e)-(1-2/m)*e*(diff(H(e), e)) = 0

eq[2] := diff(H(e), e) = t(e)

eq[3] := 5*(diff(t(e), `$`(e, 2)))/Pr+(1+3/m)*F(e)*(diff(t(e), e))-5*(diff(F(e), e))*t(e)

eqs := eq[1], eq[2], eq[3]

I asked a question few hours ago. I corrected the error in the process I was suggested. How in writing the program to collect the coefficients of m^0, m^1 and m^2, I am again stuck in an error and could not find any help.

restart; N := 2

Eq[1] := diff(f(eta), `$`(eta, 3))+(m+4)*f(eta)*(diff(f(eta), `$`(eta, 2)))-(2*(m+1))*(diff(f(eta), eta))^2-(2*(m+1))*h(eta)-(.5*(m-2))*eta*(diff(h(eta), eta))

Eq[2] := g(eta)-(diff(h(eta), eta))

Eq[3] := (diff(g(eta...

How can I get this expression, ln(1+y²/(x-1)²)+2ln(x-1) , to simplify to ln((x-1)²+y²) ?  I would think Maple should be able to do that.  Thanks, Ratch

Hello everyone. I am new to Maple. I am trying to simplify an expression in Maple. The expression is like:

u := a+b*x+a/x+b*x^7+c

If I use simplify(u) Maple returns the result as:

 (a*x+b*x^2+a+b*x^8+c*x)/x

If I want the result in the form:

u = a*(x+1)/x+b*x*(1+x^6)+c

or

u = a*(1+1/x)+b*x*(1+x^6)+c

How should I proceed? Is it possible to do this?

Hello

i want to simplify this expression (f@f@...@f@f)(x)

f is repeated "n" times

e.g: for n=3

we found (f@f@f)(x) .

help me please.

Noticed that after simplify memory remains in some internal caches. How to free it after simplification done?