AHSAN

165 Reputation

6 Badges

5 years, 246 days

MaplePrimes Activity


These are replies submitted by AHSAN

@sand15 

 I do not understant about loop? I could not talking about loop. Acutally, I want to calculate decrease or increase in percentage of the both curve. Means the value of  expressionB is decrease 20%, 8%, or 7%  as of expression A. In your computation 

PercentageOfVariation is -8.77096392
or -19.42247313

What does its meaning or how to read it and can you please explain your whole computation or procedure you adopted.

Is it possible to show the peak or maximum value of each curve on respective curve then we calculate the decrease or incease in percentage between curves?

@mmcdara thanks for help, Actually, I am trying to caculate maximum point at which expression have maximum value and then want to check loss or increase in percentage on changing the value the of M for expression. I am following the idea from other file in which file is runnning sucessfully. I have copy that idea below in the file you created. I am consfuse and cannot understand, how to change or copy that idea for my expression.

Help_mmcdara.mw

@mmcdara thanks alot sir for kind support and help. Sir, I could find the graph for  Nu on vertical axis and k on horizontal axis for these values. Thanks alot for your help. I am trying to understand your code but its complex for me.....There is no way to draw same graph in sample way..?

beta := 0.5;Br:=0.2;Q := 0.5516;lambda := -0.0294;k := 0.1;
beta := 0.5;Br:=0.2; Q := 0.4903;lambda := -0.0343; k := 0.2
beta := 0.5;Br:=0.2; Q := 0.4290;lambda := -0.0388;k := 0.3;
beta := 0.5;Br:=0.2;Q := 0.3677;lambda := -0.0426;k := 0.4;
beta := 0.5;Br:=0.2;Q := 0.3064;lambda := -0.0451; k := 0.5;
beta := 0.5;Br:=0.2;Q := 0.2451;lambda := -0.0457; k := 0.6;
beta := 0.5;Br:=0.2;Q := 0.1839; lambda := -0.0436; k := 0.7;
beta := 0.5;Br:=0.2;Q := 0.1226;lambda := -0.0369;k := 0.8;
beta := 0.5;Br:=0.2;Q := 0.0612; lambda := -0.0227;k := 0.9;

@mmcdara Thanks alot for quick help. yes you are write the value of Beta and Br are same. Sir is it possible to change or customise values written on every bar means if we want to change other value then how could we change, Actually on every bar I need to mention the (lambda+Q=--------) and I want to customise it according to desire.

sir how to change the view of verticle axis means now the bar is in downword posiiton and is it possible to show bar from down to upper direction as mentioned in the picture that I have upload for reference.

sir last change how to plot same bar for k....in this case the value of beta and Br will remain fixed but the value of lambd and Q will change for every values of k, belose is the case

beta := 0.5;Br:=0.2;Q := 0.5516;lambda := -0.0294;k := 0.1;
beta := 0.5;Br:=0.2; Q := 0.4903;lambda := -0.0343; k := 0.2
beta := 0.5;Br:=0.2; Q := 0.4290;lambda := -0.0388;k := 0.3;
beta := 0.5;Br:=0.2;Q := 0.3677;lambda := -0.0426;k := 0.4;
beta := 0.5;Br:=0.2;Q := 0.3064;lambda := -0.0451; k := 0.5;
beta := 0.5;Br:=0.2;Q := 0.2451;lambda := -0.0457; k := 0.6;
beta := 0.5;Br:=0.2;Q := 0.1839; lambda := -0.0436; k := 0.7;
beta := 0.5;Br:=0.2;Q := 0.1226;lambda := -0.0369;k := 0.8;
beta := 0.5;Br:=0.2;Q := 0.0612; lambda := -0.0227;k := 0.9;

@mmcdara thanks alot, you got my point. I am looking the graph exactly in same way. Sir I have changed the expression and try to I implement your work, ist part is working but there is no display of graph. I also want to add numeric value on the top of every bar. Kindly have a look my expression

Expression_changed_but_no_result.mw

@mmcdara  my expression is ok for line plot and its depends on lambda, Q and beta. Actually, I want to draw bar chat for different value of beta [0.1,0.3,0.5,0.7,0.9) between Nu and y ( Nu is on vertical axies and y is on horizontal axis) and crosspedning to the values of beta the value of Lambda and Q also changes. The main purpose is to check the increase or decrease in NU for beta through bar chart. I am uploading again a picture for only refernce. Please check

please upload your maple worksheet.

@acer thanks sir for help. I was looking same thing. So, nice of you.

@tomleslie thanks for your response, from figure, we can observe that the the peak of lines is decreasing like black line is below the red line or we can say that on decreasing the value of M, the curve has decreasing trend, Now I am interested to find the that decrease in percentage means we can able like in this way figure  demonstrates 37% decrease as value of M increase.

Above example run for two value and got two answer so can say that the value is decreases by 87% on changing the value of M?

@tomleslie Thanks sir, it is working accordingly.

@tomleslie I want to fix horizontal axis means y axis like Y=0..1 ....in above graph now it is from y=-1..1

@Carl Love Sir the sheet you run is also working on my side and I am using Maple 22. The difference is only side bar in your picture and in my picture. In my code there is no bar on right side of the graph. Even the colours of contours line are not visible.

@mmcdara sir now the code is working but again the colors are same. Kindly help me to show differents colors in between two contours....as like I upload a picture for reference

Please have look on my work sheet

Countour_colouring_help.mw

@mmcdara Sir, I am trying this code on my problem but got error. Can you please have look on my worksheet.

Countour_colouring_help.mw

@mmcdara thanks sir its working accordingly...sir can you please explainthat how to choose these value or what is its meaning or purpose..... data[2..-1, [1, 2] and data[2..-1, [1, 4]

First 6 7 8 9 10 11 12 Last Page 8 of 21