It's not clear to me what you are asking.  And should that last set be  {{1},{2},{3},{4},{5},{6}}?  Which set do you want to get back?

It's not clear to me what you are asking.  And should that last set be  {{1},{2},{3},{4},{5},{6}}?  Which set do you want to get back?

@mmasoudsf The problem begins with LLL3:=LLL22-LLL12=RR1ans; RR1ans is assigned an equation, so you end up with an equation on the rhs.

@mmasoudsf The problem begins with LLL3:=LLL22-LLL12=RR1ans; RR1ans is assigned an equation, so you end up with an equation on the rhs.

@strangewrap Extending pagan's answer slightly. Another way---actually the same way, but via a different input---to do this is to use ?unapply with the numeric option. Thus

y00 := unapply(t,t,'numeric'):

should produce the equivalent procedure, usable in dsolve.

@strangewrap Extending pagan's answer slightly. Another way---actually the same way, but via a different input---to do this is to use ?unapply with the numeric option. Thus

y00 := unapply(t,t,'numeric'):

should produce the equivalent procedure, usable in dsolve.

Table() is not table(), the former returns an unevaluated function call, the latter returns a table structure. An unevaluated function call is of type polynom, same as

type(x(), polynom);
                              true

Table() is not table(), the former returns an unevaluated function call, the latter returns a table structure. An unevaluated function call is of type polynom, same as

type(x(), polynom);
                              true

@Markiyan Hirnyk That is consistent.  It is equivalent to doing type(eval(T), polynom).  The call to table() returns a table structure, and a table is not of type polynom. The reason the other calls fail is that a table is not being passed, but rather a name that is assigned a table.  A name assigned a table, module, or procedure does not automatically fully evaluate to the structure, but instead evaluates to the name. Here you are passing the full table structure to type.

Not quite. x[1] may create a table ref, but x[1] is not a table.

Not quite. x[1] may create a table ref, but x[1] is not a table.

Could you upload the worksheet that exhibits the error? You may use the green arrow (here) to do so.

@onder Which probe is the "position state"? None really appear to be converging to any value, there is a lot of "noise" on them.

@onder Which probe is the "position state"? None really appear to be converging to any value, there is a lot of "noise" on them.

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