map((t->[1,t[ ]])~, Tours);

Put on your glasses.

equa1 := diff(u(x,y), x, x)-y*(1+x) = 0;
pdsolve({equa1, u(0,y) = 0, D[1](u)(0,y) = 0}); 

May be you want this:

Explore(plot([x, x^k], x=0..1, color=[black,red], thickness=3, axes=box, title=`Lorenz Curve`), k=1...100.);

Addition. A similar application for G1:

G1:=2*int(x-x^k, x=0..1)  assuming k>=1;
Explore(plot([0,G1], x=0..1, 0..1, color=[black,red], thickness=3, axes=box), k=1...100.);
 

restart;
with(GraphTheory):
with(RandomGraphs):
P:=combinat:-permute([$ 1..7]):
L:=[seq(RandomTree(7), i=1..50)]:
U:=map(Edges, L):
f:=(x,y)->convert([seq(x=subs(zip(`=`, [$ 1..7], P[n]), y), n=1..nops(P))], `or`):
S:=[ListTools:-Categorize(f, U)]:
plots:-display(Matrix(3,4,[DrawGraph(Graph([$ 1..7], {seq({i,i+1}, i=1..6)})), seq(DrawGraph(Graph([$ 1..7],S[i,1])), i=1..nops(S)),plot([[0,0]], axes=none)]));

Even with a large number of repetitions, for some reason Maple does not generate the graph on the first picture. Therefore, it was specified for plotting manually.

 

Download PiecewiseTruncate_new.mw

add(`if`(j=1, 2^j, 3^j), j=1..2);
                                                                 11

or

add(eval(x^j, [`if`(j=1, x=2, x=3)]), j=1..2);
                                                                 11

or

f:=j->piecewise(j=1, 2^j, 3^j):
add(f(j), j=1..2);
                                                                 11

Addition.  Usually sum  command is used  for symbolic summation with an indefinite (non-numeric)  number of summands or for summing series with an infinite number of terms, for example:

sum(1/2^k, k=1..n);
sum(1/2^k, k=1..infinity);
 

plots:-implicitplot(sqrt(S)*sqrt(1+S)-arcsinh(sqrt(S))=t, t=0..3, S=0..3, color=red, labels=[t,S(t)]);

Download Explore.mw

If you want to divide both sides of the inequality  e  by  1-a, then you can do so:

d:=a>0,a<1,b>0,c>0;
e:=(1-a)*b>c;
map(`/`, e, 1-a)  assuming d;

In fact, Maple does not take into account the assumption on  a . See

map(`/`, e, 1-a)  assuming a>1;

If you use  solve  command to solve the inequality, then the assumption is taken into account:

e:=(1-a)*b>c;
solve(e, b)  assuming a<1;
solve(e, b)  assuming a>1;
                                                            

sol:=solve([sin(t), 0 < t, t < 8*Pi], t, allsolutions, explicit);
map(rhs@op, [sol]);

Addition. This can be written even shorter if we use the element-wise operator ~ (it seems it appeared in Maple 13 or 14):

(rhs@op)~([sol]);
 

I took 20 random points in the cylinder:

restart;
P1:=[seq([rand(0...evalf(2*Pi))(),rand(0...2.)(),rand(0...3.)()], i=1..20)]:
P2:=map(t->[t[2]*cos(t[1]),t[2]*sin(t[1]),t[3]], P1):
A:=plottools:-cylinder([0,0,0], 2, 3, style=surface, strips=100, transparency=0.7):
B:=plots:-pointplot3d(P2, symbol=solidsphere, color=red, symbolsize=15):
plots:-display(A, B, axes=none);

restart;
myPi_1:=proc(r)
local i,l;
l:=0;
for i from 1 to floor(r) do
    if isprime(i) and (i mod 4 = 1) then
        l:=l+1;
    end if;
end do;
return l;
end proc:    

plot('myPi_1(t)', t = 0 .. 500, numpoints = 500, thickness = 2, color = black);

To calculate the values of functions  U1  and  U, it is better to define these functions as procedures and calculate their values for each call of these procedures. Then you will not have any problems:

G1:=-0.9445379894:
f:= (x) -> 0.9/abs(x-0.4)^(1/3)+0.1/abs(x-0.6)^(1/2):
U1 := x->-exp(-x)*(int(f(t)*exp(t), t = 0 .. x)+G1)/2-exp(x)*(int(f(t)*exp(-t), t = 0 .. x)+G1)/2;
seq(U1(x), x=0..1.5, 0.1);  # Calculations of values the function U1(x)  in the different points
plot(U1, 0..1);  # The plot of U1(x)

For a function  U , everything is the same.

lst:=[1,2,3,4,5,6]:
lst[2..5];
                                                        [2, 3, 4, 5]