Advanced Search

RLessard

100 Reputation

3 Badges

7 years, 240 days
Contact RLessard

MaplePrimes Activity


These are replies submitted by RLessard

Assuming problem ....

RLessard 100
September 19 2026
0 0

I, too, have noticed that the "assuming" command doesn't always work correctly.

The result is the same as what I would get without adding "assuming.

I then re-run the command on the previous result with the "assuming" and get the desired result.

More seriously, I recently realized that sometimes "assuming" causes the desired result to disappear,

as in the following example.The last two lines should be identical.

Perhaps newer versions of Maple have fixed this issue.

 
> 

kernelopts(version);
 

`Maple 2018.2, X86 64 WINDOWS, Nov 16 2018, Build ID 1362973`

 (1)
> 

intx := Int(sqrt(1-y^2/(x^2)),x=a..b) ;

Int((1-y^2/x^2)^(1/2), x = a .. b)

 (2)
> 

op1 := op(1,intx) ;

(1-y^2/x^2)^(1/2)

 (3)
> 

normal(diff(op1,x)) assuming x>0 ;

y^2/(x^2*(x^2-y^2)^(1/2))

 (4)
> 

normal(diff(op(1,intx),x)) assuming x>0 ;

0

 (5)
 

 

Download assuming-problem.mw

new but not necessarily better...

RLessard 100
November 24 2022
0 0

 

 Hi !

My old version of Maple gives me the correct result .

Workaround ......

RLessard 100
February 21 2022
0 0

@Mariusz Iwaniuk Thank you ! But I know your solutions.    This is how I found the solution.

Rather, I'm looking for a particular command in Maple (in sumtools or Sumtools) which would give me the answer.

Thanks anyway !

Thanks !...

RLessard 100
February 20 2022
0 0

 Thanks !

  @Preben Alsholm   Thanks !    You provided me with 2 solutions .

    The  arrow  and  "option operator,arrow"  are  fine for me .

     Best Regards !

Screenshot !...

RLessard 100
February 20 2022
0 0

Hi !

Here is the screenshot of my computer with Windows XP and Maple V Release V .

I have also an old computer with Windows 2000  .  Same screenshot ! 

  Best regards !

Thank you !...

RLessard 100
February 20 2020
0 0
 
Sorry for the screenshots !

Mr. Carl  Love , thank you very much !
The trick is to eliminate the term (2*i + 2*k)!  keeping only (2*i)!  and use convert (exp, parfrac).

As you probably guessed, I want to calculate the infinite summation according to the variable k.
The commands in the file "solution.mw"   work fine for different values of k  .
 
Best Regards 
Réjean
 
Page 1 of 1