janhardo

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11 years, 153 days

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These are replies submitted by janhardo

@vv 

Thanks 

As i understand it correct : S series is included in F series. 
But there is a given series S and how  to know at forehand that series F is related with series S ?

@Carl Love 

Thanks 

I am puzzling on the first book example for a given sum  how this to get  by  a integral.
Yes, there is studymaterial about power series. 

Seems to be useful infinite series handling, probably in further programming tasks? 

 

    

Is there a connection between of a function with his:   derative, integral and serie ?

 

@Carl Love 

Thanks

Yes, i understand it that you mention it for completeness.

Complex analyse is not that easy as it is for real numbers.

  
 
 

@acer 

Thanks, indeed this question has nothing to do with complex numbers and know nothing about complex functions

 

@Carl Love 

Thanks

I do have  some basic understanding of complex numbers, but complex functions( analyse) i did not yet studied.
 

 

@Carl Love 

Thanks
I did 

convert(ln(1+x),FPS); and get 

 Sum((-1)^k*x^(k + 1)/(k + 1), k = 0 .. infinity)  = 

But value(sum((-1)^k*x^(k + 1)/(k + 1), k = 0 .. infinity)); gives back again 

 

So f(x)= ln(1+x)   gives a serie, but this serie gives not the function back
Domain is < 0 to ? from ln(1+x)  and serie start at x = 0
It must be functions what their domain ranges from 0 ...n  to get from a serie a function back then?   

  

Don't know how to handle this vectorvalued function task for 4 points with tangentlines (or velocity lines?) and accelleration lines 

There was a task made  with a parametric curve also with 3 points and tangentlines, but the vectornotation differs
I tried task 8(i) for curve see post

I choose 4 points from t = 0 ,1/4 , 1/2, 3/4  (they must no too close and interesting )

blz35.pdf

blz36.pdf

hfdts2_blz37.pdf

  

@vv 

Thanks

Is it possible to get a function from a FPS serie ?

Expanding the integrand in a Maclaurin series ( as book tip ) : the integrand is here : ln(1+x).

 

 

@janhardo 

I must use this form for the vectorfunction in task 8

s(t):=[t^5-t+1,2*t^6-t^2-t+1,t=-1..1.2], labels=[x,y];


 

restart; with(plots): with(DEtools): with(VectorCalculus):

r(t):=[cos(t),sin(t),t=0..2*Pi], labels=[x,y];

[cos(t), sin(t), t = 0 .. 2*Pi], labels = [x, y]

(1)

plot(r(t)):

s(t):=[t^5-t+1,2*t^6-t^2-t+1,t=-1..1.2], labels=[x,y];

[t^5-t+1, 2*t^6-t^2-t+1, t = -1 .. 1.2], labels = [x, y]

(2)

 

plot(s(t));

 

========================================================

standaard parametrisch eplot ..nu via vector

V:=<cos(t),sin(t)>;

Vector(2, {(1) = cos(t), (2) = sin(t)})

(3)

 

2D curve defined parametrically by a free vector, graphed with the SpaceCurve command

 

SpaceCurve(V,t=0..2*Pi):

 

R:=<t^5-t+1,2*t^6-t^2-t+1>;

Vector(2, {(1) = t^5-t+1, (2) = 2*t^6-t^2-t+1})

(4)

SpaceCurve(R,t=-1..1.2);

 

 

===========================================================

R:= PositionVector([cos(t),sin(t)]);

Vector(2, {(1) = cos(t), (2) = sin(t)})

(5)

PlotPositionVector(R,t=0..2*Pi,curveoptions=[color= red],tangent=true): # is niet goed bij vraagstuk 8 exc set 2

 

PositionVector graphed by PlotPositionVector command

 


 

Download info__parametrisch_en_vectorfunctie.mw

@Carl Love 

Thanks

I read here : "formal power series can be seen as an extension of polynomials. We speak of “formal” series, because we are not worried about convergence issues."

But it is still not clear how the proven serie has a connection with the serie expension of this integrand function : how are those two series related ?

Th e proof is not yet fully understood, but maybe later? 

 

@vv 

Thanks

Can't follow the proof , because i don't know what the intended use for some commands is ( F,Sx and S )

Is it a proof by induction ?

Also the task introduce a integral and suggest to expand the integrand in a serie for getting  also a proof ?

@tomleslie 
Thanks!

I use also help in Maple, yes
Your explanation should also to be read in the manual ?

@tomleslie 

Thanks 

It is all understood now with the graphs, but suppose should i try to program this, then i need the plots of the left-hand-right-hand and mid-sum, that's i what a mean there.
My sentence was not complete, sorry. 

----------------------------------------------------

One command seq has a question : there is a  [ ] included  :  a list-building operator to initialize a list construction ? 

seq
                   ( [ [ X[i],   Y[i+1] ],
                       [ X[i+1], Y[i+1] ]
                     ][ ],
                     i=0..N-1
                   ),
--------------------------------------------

Also filling 1 Array Ymid  is little bit complicated with nested ~  


Ymid:=f~(X+~(b-a)/(2*N)); # X+ 1/2 partition 
indeed powerful with only this ~ symbool to do this

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