Hi let's say i have a list like this one u:=[1,2,5] i want to know the max that is 5 in this case how to do that thank you

hi lets say i have 2 functions
h:=x->piecewise(x <= 5, x-1, x <= 7, 4, x <= 15, 18-2*x);
h1:=x->piecewise(x <= 3, -3/2+(3/2)*x, x <= 5, 3, x <= 15, 21/2-(3/2)*x);
i'm looking for, when h1(x)=h(x)
when i plot it
plot({h(x), h1(x)}, x, thickness = 3);
i can see 2 intersections
when i do
fsolve(h(x)=h1(x),x);
it returns me only one solution =1
is there any alternative to this
Normally i should have 2 solutions in the interval 1 until 10 , that are x1=1 and x2=4
thank you

is it possible ti split the sreen of maple thank you

Hi let's say i have 2 functions the first one is f :=x->[[1, 0], [3, 3], [5, 3], [7, 0]]; the second one is g :=x->[[1, 0], [5, 4], [7, 4], [9, 0]]; when i use plot({f(x),g(x)}); i can see the both functions and the intersection but I don't know how to calculate the intersection Can you help me please thank you .