Maple 17 Questions and Posts

These are Posts and Questions associated with the product, Maple 17


Can you please tell how the guess vector is defined in Newton's method in "fsolve" if not set initial interval for unknowns? Maybe someone knows what "norm of errors", "new norm" and "incr" in "infolevel[fsolve]" are?


Could anyone explain why Maple doesn't calculate the Killing vectors for the metric below?

Thanks in advance!

On the convex part of the surface we place a curve (not necessarily flat, as in this case). We divide this curve into segments of equal length (in the text Ls [i]) and divide the path that our surface will roll (in the text L [i]) into segments of the same length as segments of curve. Take the next segment of the trajectory L [i] and the corresponding segment on the curve Ls [i], calculate the angles between them. After that, we perform well-known transformations that place the curve in the space so that the segment Ls [i] coincides with the segment L [i]. At the same time, we perform exactly the same transformations with the equation of surface.

For example, the ellipsoid rolls on the oX1 axis, and each position of the ellipsoid in space corresponds to the equation in the figure.


And similar examples:


I want to solve quadratic eqution involving more than 2 parameters...want to analize unique soltuions and real roots also want to plot the real and unique region on graphs ....thanx

the equation is -delta*(Q*S*alpha*b-a*alpha^2+M*c+b*delta) where alpha is the varible and rest are paramters 




Assume we have the following "intervals" (I am not sure what is its formal name in Maple)


C :=[0,1/11],[1/11,1/9],[1/9, 1/7],[1/3,1/2],[1/2,1]


How can we get the "union" of these intervals? That is to say, obtain  [0,1/7],[1/3,1] 


Many thanks in advance for your comments and suggestions.




Assume we have the first N positive integres, 1,..,N, and we assing to these numbers a (discrete) probability distribution p1,...,pN. Of course, p1+...+pN=1.

Then, How can we select a number in {1,..,N} according to the given probability distribution? That is, the number 1 can be chosen with probability p1, 2 with a probability p2, etc.

Many thanks in advance for your comments.

Hello everyone, i've a problem working with Maple because i have a really big system of equations and for everything that i have to do with them, for example, collect terms, coefficients, take a lot of time from me. The problem it is when, for example, i wait 30 minutes to take the coefficients from a equation and in the next command Maple might stop, then i have to close and start all over again... My question it is if have anyway to save my file in a way that if i close and re open i dont have to compile all again. Maybe this is pretty obvious but i really dont know how to do it, because if i close my work and open again, i have to compile everything again.

I need to build this model:
We consider a population of female salmon, they live 4 years. Survival for first three years respectively: 0.5%,7%,15%. Each salmon has female kids only in 4 year and produces 5000 female offspring


If 0 occurs in the first element, I want to remove the list containing zero and the associated number.


p := [[[0, 5], [3, 10], [1, 20], [0, 50]], [[2, 5], [0, 10], [2, 20], [0, 50]]]

after processing:

[[[3, 10], [1, 20]], [[2, 5], [2, 20]]]

I tried in vain...

select(i -> (subs(p,p[1,i,1])>0), [$1..nops(p)]);


Do not have a working activation code for Maple17.  Have these 2, but neither works.



I am running Ubuntu 18 (linux).


Tom Vawter

(John Vawter)


We produce only one rotation of the cube by the angle Pi/2, and then repeat it at the following points, changing the colors of the faces in turn. And so the illusion is created that the cube is rolling along a straight line without slipping.
(Just a picture without any sense.)


I am trying to plot 2 equations divided in 3 intervals (, tr..te, te..tfin1), but when i try to solve the first equation it appears:

"Warning, cannot evaluate the solution further left of .66099564e18, probably a singularity"

Is it possible avoid this point?

About the second equation, when i try to solve between "te and tr" the program says that the argument is invalid.

Can someone help me?

Here is the program:


Digits := 20;

M := 0.122e20*0.152e25;
kappa := evalf(sqrt(8*Pi/M^2));
rrhoCC := 0.769e-41*(0.1e-28*0.561e24)*0.152e25^4;

rrhoM0 := 0.1e51;
rrhoR0 := 0;
rrhoM := proc (t) options operator, arrow; rrhoM0/a(t)^3 end proc;
rrhoR := proc (t) options operator, arrow; rrhoR0/a(t)^4 end proc;
pM := proc (t) options operator, arrow; 0 end proc;
eq1 := diff(a(t), t) = a(t)*kappa*sqrt(rrhoM(t)+rrhoCC)/sqrt(3);
eq2 := 2*(diff(a(t), t, t)) = -(1/3)*kappa^2*(rrhoM(t)+3*pM(t)-2*rrhoCC)*a(t);
tini := 0.1e19;
sys1 := {eq1, a(tini) = 1.0};
sys2 := {eq2, a(tini) = 1.0, (D(a))(tini) = 0.284e-17};
tfin1 := 0;
te := 10^(-32);
tr := 10^12;
singularities(eq1, a(t));
singularities(eq2, a(t));
p1a := dsolve(sys1, type = numeric, abserr = 10^(-15), relerr = 10^(-15), range = tini .. tr);
p1b := dsolve(sys1, type = numeric, abserr = 10^(-10), relerr = 10^(-10), range = tr .. te);
p1c := dsolve(sys1, type = numeric, abserr = 10^(-10), relerr = 10^(-10), range = te .. tfin1);
fig1a := odeplot(p1a, [t, a(t)]);
fig1b := odeplot(p1b, [t, a(t)]);
fig1c := odeplot(p1c, [t, a(t)], color = red);
display(fig1a, fig1b, fig1c);
p2a := dsolve(sys2, type = numeric, abserr = 1.*10^(-12), relerr = 1.*10^(-12), range = tfin1 .. te);
p2b := dsolve(sys2, type = numeric, abserr = 1.*10^(-12), relerr = 1.*10^(-12), te .. tr);
p2c := dsolve(sys2, type = numeric, abserr = 1.*10^(-12), relerr = 1.*10^(-12), range = tr .. tini);
fig2a := odeplot(p2a, [t, a(t)], color = green);
fig2b := odeplot(p2b, [t, a(t)], color = green);
fig2c := odeplot(p2c, [t, a(t)], color = green);
display(fig2a, fig2b, fig2c);




It post can be called a continuation of the theme “Determination of the angles of the manipulator with the help of its mathematical model. Inverse  problem”.
Consider  the use of manipulators as multi-axis CNC machines.
Three-link manipulator with 5 degrees of freedom. In these examples  one of the restrictions on the movement of the manipulator links is that the position of the last link coincides with the normal to the surface along the entire trajectory of the working point movement.
That is, we, as it were, mathematically transform a system with many degrees of freedom to an analog of a lever mechanism with one degree of freedom, so that we can do the necessary work in a convenient to us way.
It seems that this approach is fully applicable directly to multi-axis CNC machines.

(In the texts of the programs, the normalization is carried out with respect to the coordinates of the last point, in order that the lengths of the integration interval coincide with the path length.)

I am trying to use Monte Carlo integration example given at:

After coding the procedure, the statement approxint(x^2, x = 1 .. 3)

gives error: Error, (in approxint) invalid input: `if` expects 3 arguments, but received 1

But I have used in exactly the same way as given in the page. What is the problem


Realted to this post I am trying to solve the following inequalities in the variable "t"




Cosenos := proc (m, x) local C, x1, x2, y, x0, i, j, j0, k, K0, Kaux, K1, L, R, S, t1, t2, t, r1, r2, d; C := NULL; K0 := NULL; Kaux := NULL; K1 := NULL; L := NULL; R := NULL; S := NULL; d := nops(x); for k to d-1 do if evalf(x[k]) = 1 then j0 := m else j0 := 1+floor(x[k]*m) end if; K0 := K0, [(j0-1)/m, j0/m] end do; K0 := [K0]; S := K0[1][1] <= t, t <= K0[1][2]; for k from 2 to d-1 do S := S, K0[k][1] <= 1/2-(1/2)*cos(Pi*m^(k-1)*t), 1/2-(1/2)*cos(Pi*m^(k-1)*t) <= K0[k][2] end do; K1 := solve({S}, t) end proc


However, this run very very slow....For instance, for Cosenos(50, [.3225, .25877, .325, 1])


we interrupt the opertion after more than 10 minutes...I am doing something wrong?

Many thanks for your comments and suggestions. 




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