Maple Questions and Posts

These are Posts and Questions associated with the product, Maple

I know very little about the Kalman filter. The thing that I do know is that the Kalman filter has great potential.

However I am not sure that I want to invest time doing reasearch on it because I am not sure I

will be able to come up with an working model in Maple. Does anyone have any experience with Kalman filter in Maple ?

Does anyone want to explain how such a model works ?!

HI there, I have a quick question and I just want to confirm what I found. I was trying to do some Fourier Transform using the MTM package and I was successful in doing so for one dimensional problems when it's only f(x) but when I tried to do something more complicate like 2D fourier transform when the f is a function of x and y ie. f(x,y), Maple seems not able to do it. I checked with help menu and it seems it can support only 1D. is there anything other package that I'm not aware of that is capable of a such thing?

Greetings All

I just wanted to test some values in the Rydberg Formula:

eq1 := 1/L = R(1/nfinal^2-1/nstart^2)

sol1:= solve(eq1, L)

and the answer looks correct:

1/R(-(-nstart^2+nfinal^2)/(nfinal^2*nstart^2))

 

But when I go and try and solve for these other variables I get

solve(eq1, nfinal)  ----->  I get an "Error, (in evala/Reduce/ff/monomial) numeric exception: division by zero"

solve(eq1, nstart)  --->   I get nfinal^2/(-1+RootOf(R(_Z)*L-1)*nfinal^2)

http://demonstrations.wolfram.com/LearnTheGameOfGo/

here is a simple expamle,but it's not a game.

And the computer's AI can be developed.

If anyone know should use which programming language,I know C,C++,matlab,mathematica,

and what's that I should learn?

 

Hi,

I often use  the display(plot1, plot2, ..., axis[1]=[tickmarks=[0,100,200,300,400], gridlines=[5, subticks=true]], axis[2]=[tickmarks=8, gridlines=[8, subticks=true]]) command to plot several plots in one and to adjust the gridlines to what looks better than the default.

I'm spliting up a number into a list but I'm not sure if this is the best way.

a:=74.367854;

b:= convert(a, string);

with(StringTools);

c:=Select(IsAlphaNumeric,b);

d:=Explode(c);

e:=seq(parse(d[i]),i=1..nops(d));

                                            7,4,3,6,7,8,5,4

I need the formal solution to the inverse of (d(m) = sum of c(k)/(k-m)! from k = m+1 to j  for all m from 0 through j-1). Egorychev's theory of turning summations into complex integrals seems to work only on his chosen examples, namely, where the summation index, k, is the lower variable in the binomial coefficient, not the upper variables as in my case k-choose-m, if one redefines c(k) as c(k)*k! and d(m) as d(m)*m!  Any ideas?  Thanks! 

Hi, I got a simple question. I want to use the add function but with an increment rather than 1. for example add(a[i], i = 1 .. 4) gives a[1]+a[2]+a[3]+a[4], whereas I want to have a[1]+a[3] for instance. Please let me know how I can define it that way. Thank you,

00:00:10,980 --> 00:00:12,780
it will not have gone though both slits.

> Why these spineness appeared in some certain value?for example

> But if x is not the value +-1.5,it doesnt appear.

Good Morning,

Would anybody in the community please help me  to trouble shoot the problem with fsolve not producing result.

Regards,

<p> </p>
<p><img alt="" src="file:///C:/DOCUME~1/sanjay/LOKALE~1/Temp/moz-screenshot-18.jpg" /><img alt="" src="file:///C:/DOCUME~1/sanjay/LOKALE~1/Temp/moz-screenshot-19.jpg" /><maple>e < proc (n) options operator, arrow; (1+1/n)^((1/8)*(n^(1/3)+(n+1)^(1/3))^3) end proc</maple></p>

a:=seq(1/x,x=1..10);

b:=evalf(a,4);

c:=matrix(2,10,[[a],[b]]);  

How do I swap this to a 2 column 10 row matrix.

 

The topic maybe not so rigor.

question1:

For example,here are four complex numbers.

B ={3/13 - (2 I)/13, 3/2 - (5 I)/2, -(7/2) - 13 I, 1 - 3 I}

List B can be easily manipulate like this in mathematica,

Re(B),Im(B)

In[31]:= Re[A]
Out[31]= {3/13,3/2,-(7/2),1}
In[32]:= Im[A]
Out[32]= {-(2/13),-(5/2),-13,-3}

and in maple,I creat the array like this:

n := (a, b, c, d)

a,b,c,d are the four elements corresponding  to List B above.

A:=Array([a,b,c,d])

hi

how can i find the convergence rate of the sequence:

 

(1+1/n)^n

 

how can i show that

(1+1/n)^(n+1/2) converges faster than (1+1/n)^n

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