How do I extract all the coefficients of a partial differential equation?

Question:How do I extract all the coefficients of a partial differential equation?

Posted: mary120 65 Product: Maple 11

April 12 2020

I want to extract all the coefficients of a PD equation.

For example, let

dn0/dt+depsilonn1/dt+depsilon^(3/2)n2/dt+depsilon^2n3/dt+epsilondn0u1/dx+epsilon^(3/2)dn0u2/dx+dn0epsilon^2u3/dx+depsilon^2n1u1/dx+depsilon^(5/2)n1u2/dx=0

(power expansion of countinuty eq. ). I want to extract the terms with coefficint $epsilon^3/2$ that is:

d/dt(n_2)+d/dx (n0u2)

Thanks

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Question: How do I extract all the coefficients of a partial differential equation?

Question:How do I extract all the coefficients of a partial differential equation?

I want to extract all the coefficients of a PD equation.

For example, let

dn0/dt+depsilonn1/dt+depsilon^(3/2)n2/dt+depsilon^2n3/dt+epsilondn0u1/dx+epsilon^(3/2)dn0u2/dx+dn0epsilon^2u3/dx+depsilon^2n1u1/dx+depsilon^(5/2)n1u2/dx=0

(power expansion of countinuty eq. ). I want to extract the terms with coefficint $epsilon^3/2$ that is:

Question: How do I extract all the coefficients of a partial differential equation?

Question:How do I extract all the coefficients of a partial differential equation?

I want to extract all the coefficients of a PD equation.

For example, let

d*n0/dt+d*epsilon*n1/dt+d*epsilon^(3/2)*n2/dt+d*epsilon^2*n3/dt+epsilon*d*n0*u1/dx+epsilon^(3/2)*d*n0*u2/dx+d*n0*epsilon^2*u3/dx+d*epsilon^2*n1*u1/dx+d*epsilon^(5/2)*n1*u2/dx=0

(power expansion of countinuty eq. ). I want to extract the terms with coefficint $epsilon^3/2$ that is:

dn0/dt+depsilonn1/dt+depsilon^(3/2)n2/dt+depsilon^2n3/dt+epsilondn0u1/dx+epsilon^(3/2)dn0u2/dx+dn0epsilon^2u3/dx+depsilon^2n1u1/dx+depsilon^(5/2)n1u2/dx=0