Question: How can I make the list into environment \begin{enumerate} \end{enumerate} of LaTeX?

I have a list

mylist := [[sqrt(-5*x^2 - 5*x - 1) = -4*x - 1, {-1/3, -2/7}], [sqrt(-5*x^2 - 5*x - 1) = x + 1, {-1/2, -2/3}], [sqrt(-5*x^2 - 5*x - 1) = 4*x + 3, {-2/3, -5/7}], [sqrt(-5*x^2 - 5*x + 4) = -5*x + 3, {1/2, 1/3}], [sqrt(-5*x^2 - 4*x + 2) = -5*x + 2, {1/3, 1/5}], [sqrt(-5*x^2 - 4*x + 2) = -2*x + 1, {-1/3, 1/3}]]

I tried
latex(mylist) and get
 

\left[\left[\sqrt{-5 x^{2}-5 x -1} = -4 x -1, \left\{-{\frac{2}{7}}, -
{\frac{1}{3}}\right\}\right], \left[\sqrt{-5 x^{2}-5 x -1} = x +1, 
\left\{-{\frac{2}{3}}, -{\frac{1}{2}}\right\}\right], \left[
\sqrt{-5 x^{2}-5 x -1} = 4 x +3, \left\{-{\frac{5}{7}}, -{\frac{2}{3}}
\right\}\right], \left[\sqrt{-5 x^{2}-5 x +4} = -5 x +3, \left\{{\frac
{1}{2}}, {\frac{1}{3}}\right\}\right], \left[\sqrt{-5 x^{2}-4 x +2} = 
-5 x +2, \left\{{\frac{1}{3}}, {\frac{1}{5}}\right\}\right], \left[
\sqrt{-5 x^{2}-4 x +2} = -2 x +1, \left\{-{\frac{1}{3}}, {\frac{1}{3}}
\right\}\right]\right]

How can I get  a latex like this?

\documentclass[12pt,a4paper]{article}
\usepackage[left=1.5cm, right=1.5cm, top=2cm, bottom=2cm]{geometry}
\usepackage{fouriernc}
\usepackage{enumitem}
\usepackage{amsmath}
\begin{document}
	Solve the following equations:
	\begin{enumerate}[label=\arabic*)]
		\item $\sqrt{-5 x^{2}-5 x -1} = -4 x -1.$ \hfill Answer: $\left\{-{\dfrac{2}{7}}, -{\dfrac{1}{3}}\right\}.$
		\item $\sqrt{-5 x^{2}-5 x -1} = x +1.$ \hfill Answer: $\left\{-{\dfrac{2}{3}}, -{\dfrac{1}{2}}\right\}.$
		\item $\sqrt{-5 x^{2}-5 x -1} = 4 x +3.$ \hfill Answer: $\left\{-{\dfrac{5}{7}}, -{\dfrac{2}{3}}\right\}.$
		\item $\sqrt{-5 x^{2}-5 x +4} = -5 x +3.$ \hfill Answer: $\left\{{\dfrac{1}{2}}, {\dfrac{1}{3}}\right\}.$
		\item $\sqrt{-5 x^{2}-4 x +2} = -5 x +2.$ \hfill Answer: $\left\{{\dfrac{1}{3}}, {\dfrac{1}{5}}\right\}.$
	\end{document}