Question: Integral of 1/cosh x?

I've been struggling with the integral 1/(1+x^2)^2 ... i managed to use the substitution x=sinh(x) to get it into the form 1/cosh x but now im stuck! im not sure if the initial substitution was even right ... any help much appreciated! ps i know this is not strictly a 'how to' maple qu ut i thought youd all be the type of people that could help me!
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