Advanced Search

Question: substitutions don't substitute

Question:substitutions don't substitute

Michael 222 Maple
substitution simplification power
July 26 2006
0
Hi: I have a complicated expression containing many Maple generated terms each of which typically looks like: 12/b/(b^s)*s/sin(Pi*b)^2*Pi^2 I absolutely can't figure out how to make 1/b/b^s become b^(s+1). I have tried using "patmatch", "match", "subs", "collect" and have now run out of ideas. For example: subs(1/b/(b^s) = 1/b^(s+1),...) does nothing. Can someone please suggest a way to do this so that the end product will look like 12/b^(s+1)*s/sin(Pi*b)^2*Pi^2 Ultimately, I want to identify the exponents of b in each term. Thanks Mike
Please Wait...