Gillee

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7 years, 159 days

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``

How can I convert the result (2) to equal to the trigonometric identity (kw/s^2)*tanh(a*s/2)?

``

g := kw*piecewise(t < a, t, t < 2*a, 2*a-t)

kw*piecewise(t < a, t, t < 2*a, 2*a-t)

(1)

simplify((int(exp(-s*t)*g, t = 0 .. a)+int(exp(-s*t)*g, t = a .. 2*a))/(1-exp(-2*a*s)))

-(exp(-a*s)-1)*kw/((exp(-a*s)+1)*s^2)

(2)

``


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