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MaplePrimes Activity

These are replies submitted by Hullzie16


Thank you for inclduing this method as well, always wanting to learn new techniques! 



I didn't think to much of the messages tone, I was just grateful for a response. 

Thanks again and thank for you including another method. 


This is great thank you. My amateur status is showing. 

Will keep these comments under consideration with future "Arrays" I want to make. 

Thank you everyone who added a comment/suggestion. 

This was quite informative. 

@dharr @Axel Vogt @Carl Love

@Carl Love 

When we are telling maple that the discirminant is positive we are saying three real roots, but when doing what you described it only returns one, When it should be returning three. Is the explanation similar to what I above and that there is always imaginry contributions? 


Thank you for this. I did not know about solve,parametric. 

The issue that I am having though and maybe maple can not do what I am asking(or it is some general cubic property that I am forgetting). Is that in the solutions there is still an imaginary term. So it appears too me that analytic solutions will contain Imaginary contributions always but once numeric values for the parameters are inserted the imaginary part will become real. 

I assume there is no work around for this, and there will always be a imaginary contribution to a analytic solution?


I see that, for this particular problem I need to know when things become complex so i will omit that command. 

What exactly did you tell maple to do? I still wanna understand it a bit more. (I do appreciate the solution though). 


Thanks for that I am just curious though what exactly you did and if that is the only solution. I plugged it into my worksheet and it worked but i see there is a different between our two plots as i have a gap and yours does not, why is that?




Yes that would be a small but large thought which has escape me. 

I dont know if the expressions are real or not, thats what i want to do. I want to find the range when they are real. But since they are extremely complicated functions i was hoping plot would be enough to tell me as i have worked with other functions in different examples where they are complicated as well but stopped once they become complex.


@ecterrab This worked, but i was able to do it by hand off a simple trick. However i will use this method when i need. 

@Kitonum Ahh, thank you for that. Awesome. 



@Carl Love Thanks for that reply, it does work.

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