Zeineb

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7 years, 224 days

MaplePrimes Activity


These are replies submitted by Zeineb

@dharr 

thank you

@mmcdara 

Please, how can I select from your code only the solution that verify some assymption ( positive parameter ) as added in the code 
Stab_sssymption.mw

Thank you for your answer, 
You say you beleave that this can be done more simply, can you propose another idea 

@acer 

 

The recursive equation is proposed in my code 
B_^p is defined using B_i^{p-1} 
So, for p=1 B_^0 is known so we can determine B_i^1

B := proc (i, p, t) if p = 0 then piecewise(t < t[i-2] or t[i-1] <= t, 0, 1) else (t-t[i-2])*B_recursive(i, p-1, t)/(p*h)+(t[i+p-1]-t

@Carl Love 

Thanks for looking to my question. 

First :  the sequence alpha is defined using a general formula 
alpha[i]=(-1)^{i+1}  15/(5i-4), for i from 1 to 5 

I would like to get a simular formula like alpha[i] so that 
beta[1]=alpha[3]
beta[2]=alpha[2]
beta[3] =alpha[1]
beta[4] =alpha[4]
beta[5]= alpha[5]

can I have general form of beta[i]=.......... formula that depend only on i 

@vv 

Thank you, 
In the system of equations A , B and C must be replaced by A(t), B(t) and C(t) 
because they unknown functions 

I run the same code I get 
Error, (in ODEtools/ODESolStruc/info) incorrect ODESolStruc: expected 1 old dependent variable in the 2nd set of transformation equations; received: 0
code_solve_system_of_equations_vv.mw

I have 8 unknows functions, \Zeta_i(t,x,y,z), i=0,1,2,3 and A(t), B(t), C(t), \psi(t,x,y,z)

Thank you for your help 

@C_R 

The difference equation is the first equation in the maple code : system defined at three different times (n+1), n and n-1 

@vv 

 

thank you

@C_R 

I think everything is well now, in my code. 

A_less_than_one.mw

 

In the definition of beta_1 the loop from 1 to q is correct, beta_1 is a coefficient used  in A 

and everything run correctly 

thanks

@Carl Love 

so only one i a field, so can not get a homomorphism between them

@tomleslie 

This means that in geneal case, for a given x,y,z and w , we can always find n, a,b and c solution of the system 

Since we have many choice of x , y, z and we so for each choice we have a solution 

there are infintely many solution of the system 

@Axel Vogt 

But Maple return a zero solution 
Instead of a nonzero solution 

for a fixed x=1, y=1, z=6 and w=-1 we have 

n=4, a=-1, b-0, c=5 

is a solution for this fixed vector defined by x,y,z and w 

@vv 

Big thanks 

@vv 

The function f is defined only in the unit ball centered at zero and outside is zero. 
So, we have singularity at zero, and it is integrable in the vicinity of zero since 2< 3 

@vv 

Using polar coordinate you will integrate over the range [0,1]  the function r^(-2) r^(3-1) =1  and so integrable 

In general case, f(x)=|x|^(-alpha) times indicator of unit ball, is integrable over the unit ball if alpha< dimension of space  ( in our example alpha equal 2 < 3 ), so the function is integrable 

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