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MaplePrimes Activity

These are replies submitted by abbeykabir

@brian bovril Think i'll do that and see if i get the desired result. I have values for both  e and x. I don't know why i didn't think of fsolve initially. Thank you very much.

@Preben Alsholm  This looks good. I'll surely give it a trial. Thanks

@tomleslie  the result of convert(taylor(y(x+h), x=0, 3), polynom);

will not give me what i require. convert(taylor(y(x+h), h=0, 3), polynom) is what I want.

y(x) + y'(x)*h + (y''(x)*h2)/2! + (y'''(x)*h3)/3!

Now, suppose i have a value for y(x), y'''(x) and y''(x) and h, i can i substitute it there...

@ThU It didn't work. if observe well, distributing the denominator to each expression in the numerator will bring out "cot" while the denominator cancels out on some terms.

@tomleslie I added the line Et:=Vector(N), where N:=5 at the start of the code but i noticed it wasn't working so I commented it out.

@tomleslie I noticed that even if I declared Et to be a Vector, Et[1] would still not work unless i make it double index like you've said. Any reason for that?

@Carl Love I understand. You've answered my next question. Thank you. I actually wrote a small piece of code to construct the matrix for me but later decided to ask the forum for alternative way(s) which is far far better.

@Rouben Rostamian  This is cool thanks it worked

@Carl Love My teacher gave a dazing and kinda ugly reply. Just joking please kindly explain

z:= Matrix(N-n,n):  Z:= Matrix(N,N-n):
<<A,z>|Z> + <Z|<z,B>>;

I have no sigle idea of what it interpretes

@Kitonum That takes care of the error. Thanks


@Kitonum I modified the code to look like this and still have the error

eul := proc(x,y)
    local a,b:
    for j from 1 to 3 do
          y[j]:= y + h*fxy(a,b):
          a:= 0 + j*h:
          b := y[j]:
          yt[j] := b:
    end do:
    return yt:
end proc:


@Carl Love I'm definitely dreaming in code. Nice one and thanks a million times.

@Carl Love not all the 11 points, connect the points (5 points to the left or 6 to the right )



I dont even mind if it is possible to shade the connected regions just like the sample graph i included.


@Carl Love Thanks alot. I'll try the code and try to take the modal value as advised.

@Carl Love This looks good. I'll definitely go and try it out then give you a reply. Thanks man.

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