@Preben Alsholm 

 THANKS 

@Preben Alsholm 

Thanks so much,

I have been sending my equation.

Attached pdf files show the process of dimensionless of the equations.

Best

Advent.mw

predator_prey_scavenger.pdf

mmm.pdf

[paperhub.ir]10.1007@s11538-017-0339-5_(1).pdf

@Preben Alsholm 

Thanks so much.

So what is the conclusion?

The mentioned relation in the paper seems to be has a problem?

Is it correct?

Thanks

@Preben Alsholm 

Thanks so much,

I uploaded the original pdf file in the attachment.

Please see it.

Best Regards,

[Edit: .pdf removed for copyright reasons. DOI link instead:]

http://dx.doi.org/10.1016/j.nonrwa.2016.05.010

@dharr 

Thanks so much.

Is there a way to check to be sure about the process.

Because this is very important for me /

Thanks

@dharr 

Thanks so much.

Why the final result () is different from that mentioned in the attached pdf file?

Thanks so muchDoc2_2.pdf

could you please answer me?

Best

@Pascal4QM 

Thanks,

Why my result diff(TTR, alpha) is different from that mentioned in the pdf?

Thanks

@Carl Love 

Thanks so much.

Those inequalities should be considered at once.

Best

@Carl Love 

Dear Carl,

Could you please answer me for theses section:

1:u>0

2:1+m-q>0

3: -1<m<1

4:(1+m-q)^2-4*(m+c*q))>0

5 : s&c&q >0

The answer how changes.

Best

@Carl Love 

Thanks so much,

these conditions should be considered 

1:u>0

2:1+m-q>0

3: -1<m<1

4:(1+m-q)^2-4*(m+c*q))>0

5 : s&c&q >0

Thanks so much...

@Rouben Rostamian  

Dear Rouben,

please see newer my file in the attachment

Best

6.mw

@tomleslie 

This is the corrected file that I want to see that why in Eq 4 the amount of parameter 'h' is not equal to zero?

Best

6.mw

@Carl Love 

Thank you.

 Yes I want substitute an expression for u into p and solve the resulting equation for q (and verify)

@Rouben Rostamian  

Could you please explain more?

Is possible to edit it for me?