## 170 Reputation

7 years, 301 days

## @Kitonum  thank you soon much...

thank you soon much

## @Oliver K  thank you very much...

thank you very much

## @mmcdara  thank you so much...

thank you so much

## @mmcdara  thanks alot. you help me...

thanks alot. you help me alot sir

## @Rouben Rostamian  Yes, I understan...

Yes, I understand now. Thank you very much for your help

i can't do this. it't my equation

6000*sin(theta) - 3819.718635

## @Rouben Rostamian  Thank you very m...

Thank you very much for following my question. I mean the scale in the y direction.

## @Rouben Rostamian   Thank you very...

Thank you very much for your time.
Is there no other way? Because in this case, drawing the diagram is not correct in terms of scale. Thanks

## @mmcdara Thank you so much for your...

Thank you so much for your help! I really appreciate your assistance.

## @Kitonum  thank you sooooo much si...

thank you sooooo much sir

## @Kitonum   thank you so much...

thank you so much

## @Carl Love  I apologize. I make a ...

I apologize. I make a mistake to positive and negative values. I corrected it now. I just want the all values of the lines be written on the plot, like this picture

.

## @tomleslie  thank you so much&...

thank you so much

## @mmcdara  thank you sooooo much. y...

thank you sooooo much. you helpe me alot sir

## @Mac Dude  Thanks for answering.&n...

fortunately i find a good equation for my result .

restart;
with(Statistics);
j := Matrix(20, 3, [[70, 8, 8.468140006], [70, 10, 4.105515432], [70, 12, 2.36261199], [70, 14, 1.422093923], [70, 16, 0.9], [100, 8, 20.47249229], [100, 10, 9.618450629], [100, 12, 5.360869165], [100, 14, 3.399312905], [100, 16, 2.640399788], [130, 8, 35.90466304], [130, 10, 17.62958097], [130, 12, 9.828362586], [130, 14, 5.866863694], [130, 16, 3.799262645], [160, 8, 57.31814648], [160, 10, 34.49692774], [160, 12, 15.39340528], [160, 14, 9.991012951], [160, 16, 6.049343013]]);
for n from 2 by 0.001 to 3 do
eq := NonlinearFit(u*h^n*exp(-b*d)/(-c*d + h), j, [h, d], initialvalues = [b = 0.1, c = -30, u = 0.1], output = [parametervalues, residualsumofsquares]);
if eq[2] < 20.292 then
print(n, eq[2], eq[1]);
end if;
end do;

## @Thomas Richard  😍😍😍 thank youu...

😍😍😍 thank youuuuuu sir

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