Hi Pauline.

Thanks for the reply.

**To Acer, Georgios, Alec, Jakubi, Doug, Werner and Robert : A big THANK YOU for all the great help. **

Pauline, I have __summarised the problem __as per below, instead of asking your colleagues to go through the threads:

I have used "**Classic Worksheet Maple 12**" to compile the code below:

> restart;

> with(plots):

> p1:=plot(sin(x),x=-2*Pi..2*Pi,tickmarks=[0,0],color=black):

> p2 := textplot([[Pi,-0.05,`p`], [Pi/2,-0.05,`p/2`],[-Pi/2,-0.05,`-p/2`], [-Pi,-0.05,`-p`],[0.2,-0.05,`0`],[-3*Pi/2,-0.05,`-3p/2`],[-2*Pi,-0.05,`-2p`],[3*Pi/2,-0.05,`3p/2`],[2*Pi,-0.05,`2p`]], align=below, font=[SYMBOL,10]):

> p3 := textplot([[-0.1,1.0,`1`], [-0.1,-1.0,`-1`],[-0.1,0.5,`y`],[2*Pi+1.5,-0.05,`x`]], align=left):

> p4:= pointplot([[-Pi,0], [-Pi/2,0], [Pi/2,0],[Pi,0],[0,1.0],[0,-1.0],[-3*Pi/2,0],[-2*Pi,0],[3*Pi/2,0],[2*Pi,0]], symbol=CROSS):

> display({p1,p2,p3,p4});

Once the plot is displayed on the screen, I right-clicked on the plot, choose "Export As" -> "Encapsulated Postscript (EPS)" and then type in a name to save it.

Using Ghostview 4.9 to open this saved (eps) file, the resultant was that the graph is rotated anticlockwise by 90 degrees. The negative 3Pi/2 and negative 2Pi that are on the *x *axis becomes "plus or minus 3Pi/2" and "plus or minus 2Pi".

I have also tried to open this saved (eps) file using Adobe Illustrator CS3. The graph is still rotated anticlockwise by 90 degrees. The negative 3Pi/2 and negative 2Pi that are on the *x *axis becomes "box 3Pi/2" and "box 2Pi". The box means that an empty small square box is given instead of a negative sign.

One possible solution as suggested by **Acer** is to put a space in between the negative sign and 3p/2 in the textplot line p2 which would "cure" it. And to cure the rotation by 90 degrees problem, Acer suggested to insert an additional code:

> plotsetup(ps,plotoutput=`sine.eps`,plotoptions=`portrait,noborder`);

which will write the output to a file without showing the actual graph on the Maple worksheet.

__Another completely new problem is for the code found below.__ Is there any other simpler way of doing this in the Classic Worksheet Maple 12? The code below is long and tedious.

> restart;

> with(plots):

> p1:=plot(2*cos(1/2*x-Pi/6),x=Pi/3..13*Pi/3,tickmarks=[0,0],color=black,thickness=2):

> p2:=plot(2*cos(1/2*x),x=0..4*Pi,tickmarks=[0,0],color=black,linestyle=dashdot):

> p3:=textplot([[Pi-0.1,-0.05,`p`],[Pi/3+0.08,-0.05,`p/3`],[0.18,-0.05,`0`],[13*Pi/3-0.15,-0.05,`13p/3`],[4*Pi-0.1,-0.05,`4p`],[4*Pi/3+0.15,-0.05,`4p/3`],[7*Pi/3-0.1,-0.05,`7p/3`],[10*Pi/3+0.35,-0.05,`10p/3`],[2*Pi,-0.05,`2p`],[3*Pi,-0.05,`3p`]],align=below, font=[SYMBOL,10]):

> p4:=textplot([[-0.1,2.0,`2`],[-0.1,-2.0,`-2`],[-0.1,1.0,`y`],[13*Pi/3+1.5,-0.05,`x`]],align=left):

> p5:=pointplot([[Pi/3,0],[4*Pi/3,0],[7*Pi/3,0],[10*Pi/3,0],[13*Pi/3,0],[2*Pi,0],[3*Pi,0],[4*Pi,0],[0,2],[0,-2]],symbol=CROSS):

> p6:=textplot([[4*Pi/3+0.6,1,`y=2cos(x/2-`],[Pi-0.5,-1,`y=2cos(x/2)`]]):

> p7:=textplot([4*Pi/3+1.4,1,"p"],font=[SYMBOL,12]):

> p8:=textplot([4*Pi/3+1.6,1,` /6)`]):

> display({p1,p2,p3,p4,p5,p6,p7,p8});

Have a great weekend! :)

Chris