@vv Now simplify does the work for me

@Kitonum For each value of A, I need an m value (real number), but here only complex values.

If there are no real solutions to the equation then can I get the real value of m for which f(m) is closest to zero. I have a code like the following one

Some times the values obtained using this code and the functional value at that point mismatch.

@Christian Wolinski  Dear Sir, I encounterd this problem in probability theory. Parameters can take any value as long as the expression is consistent except α and β which are less than 1. m is a positive real number.

I have attached the maple program. This is just an extension of the original problem to include a sequence of m in the denominator.

test.mw

@Kitonum  Dear Sir

I have attached the maple program. I am unable to get the values of m after extending the problem to include a sequence of m in the denominator.

test.mw

@Markiyan Hirnyk I have written the code on my own. But i think this code can be reduced further with the experts. 

Doc1.pdf

@Markiyan Hirnyk Here I have denoted d/dt {dF(t)} by dF and dF(t) was written instead of dF dt. 

Download correctedex_1.mw

@Markiyan Hirnyk

I have checked the correctedex.mw code and the solution (value of Z) doesn't satisfy the equation

Please check the code I have attached.

Download correctedex_1.mw

@Markiyan Hirnyk Thank you very much

@Carl Love 

I have attached the maple program where fnormal fails to do the cancellation of factors.

checking.mw

@Carl Love 

I used fnormal to cancel nonzero factors only.

I want to cancel the zero factors, but I don't know how to do that?

e.g., I want to cancel R(x)=x f(x)/(x-4.94866427965495204 10^(-101)) g(x)

as 4.94866427965495204 10^(-101) is approximately equal to 0. I want to cancel the factor x with (x-4.94866427965495204 10^(-101)).

I think, I am clear to you now?

@Markiyan Hirnyk  it works fine

@Markiyan Hirnyk  I forgot to give braces at proper places. My question was a rational function whose numerator consists of 17 factors and the denominator consists of 18 factor between which 9 factors are matching up to 10 digits. I want to get the 10 factors cancelled automatically by the code.

@Markiyan Hirnyk  My R(s) contains 17 factors in the numerator and 18 factors in the denominator, out of 9 factors are to be cancelled as they match upto 10 digits. 

@Kitonum if i want to write the code only for the product of linear factors missing an intermediate factor

i.e. (s-a_1)(s-a_3)(s-a_4)(s-a_5)...(s-a_100) then what to write

@ecterrab Can you please give a working example with maple code for that.