toandhsp

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12 years, 146 days

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These are replies submitted by toandhsp

When i try the programs of Kitonum 175 and Joe Rien, i get different answers. I don't understant.

Thank you very much.

Thank you very much.

How i can find the values of f(k) with  
f:=k->Pi/9+2*k*Pi/3 
and k is solutions of 
isolve({(1/9)*Pi+2*k*Pi*(1/3) >= 1, (1/9)*Pi+2*k*Pi*(1/3)<= 2^Pi});
Please help me. Thank you.

How i can find the values of f(k) with  
f:=k->Pi/9+2*k*Pi/3 
and k is solutions of 
isolve({(1/9)*Pi+2*k*Pi*(1/3) >= 1, (1/9)*Pi+2*k*Pi*(1/3)<= 2^Pi});
Please help me. Thank you.

Thank you very much.

Thank you very much.

Thank you very much.

Thank you very much.

Thank you.

Thank you.

How can i convert M :=<1,-1,3> into point(M, 1, 2, 3)? Please help me. Thank you very much.

How can i convert M :=<1,-1,3> into point(M, 1, 2, 3)? Please help me. Thank you very much.

This is my algebraic method. Note that, u:=<a,b,c> is direction vector of the line Delta.

restart;with(geom3d): with(LinearAlgebra):

A:=<1,-1,3>:

plane(P,x+y+5*z=0,[x,y,z]):

line(l, [2*t,-5*t, 6*t],t):

n:=convert(NormalVector(P),Vector):

v:= convert(ParallelVector(l),Vector):

u:=<a,b,c>:

w:=CrossProduct(v,u):

d:=abs(DotProduct(w,A,conjugate = false))/Norm(w,2):

solve([a^2 + b^2 + c^2 = 1, d = 1, DotProduct(n,u, conjugate = false)=0],[a,b,c]);

First, many thanks to Kitonum. Because i want to have a beautiful answer, therefore, i write the equation circle passing three points A, B, C. And then, write the equation tangent of the circle (ABC) at the point C. Thus, the line is this equation of this tangent. Now, i hope Kitonum understand my idea. Thank you again.

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