@Carl Love Kind help attached error error_in_my_system.mw
Second one change in my way of question i found when was excecuting Kitonum 18884 I found a blunder in the way I questioned my problem.
The number of columns and rows is immaterial in the matrix
Now let one row of matrix A has say [0,1,2,2,1,2,3,2,3,4,1,1]
Let one row of matrix B has say [0,1,2,1,2,2,3,2,3,1,1,4]
forgetining the number of zeros,
The 1 has occured 4 times in that row in A , similiarly 1 has occured 4 times in B in a row
in the same row 2 has occured 4 times in A , similiarly 2 has occured 4 times in B in that same row
simiarly 3 has occured 2 times in the same row in in A, similiarly 3 has occured 2 times in B in that same row
similiarly 4 has occured 1 times in the same row in in A, similiarly 3 has occured 1 times in B in that same row
So both rows have same number of occurences of the non-zero elements then we say that those to rows of A and B are same.
That is based on number of occurences of the non-zero elements
A=[4,2,2,1] and B=[4,2,2,1] first denotes the number of occurence of 1, next denotes number of occurence of 2 and third the number of occurence of 3 and fourth the number occurrence of 4
so if their are extra higher number it will go upto that then we can check the regular equality of the both in the order. need help kind help.
If not those two rows are not equal.
So now to find how many rows are same with the above condition or all rows not equal to the other at all in both matricies A and B
Please kind help it will be acknowledged