In this episode Tom talks with Dr. Janos Pinter about how to optimize decisions under resource constraints, the early days of computing, and his thoughts about studying in a communist country. He joins us via telephone from Halifax, Nova Scotia. Eithne Murray stops by again to discuss the fascinating world of programming in Maple; and we have also information about using the new Intel-based Mac port of Maple and a new e-book on understanding and computing derivative securities. Click here to get the latest episode.

> (MathML[Import])("<math>
<mrow>
<munder>
<mrow>
<mi>lim</mi>
</mrow>
<mrow>
<mi>x</mi>
<mo>→</mo>
<mi>a</mi>
</mrow>
</munder>
<mi>x</mi>
</mrow>
</math>");

lim x

it took some time, a little help by this forum and the excellent maplesoft-support, but here is how it worked on my SuSE 10.1: As root: -Create a directory and copy your installation files into it, i.e. from the delivered CD -The trick is to edit the installer script with binary mode vim (using the -b flag: vim -b LinuxInstaller.bin) -Then scroll down to the first instance of "export LD_ASSUME_KERNEL" and replace the 'e' in 'export' with '#'. This comments out the line and evidently leaves the installer size intact so those compression errors are bypassed -Save and quit the file As your maple-user:

A couple of my Maple Net worksheets.... McCabe-Thiele Distillation View 54_McCabe-ThieleDistillation.mw on MapleNET or Download 54_McCabe-ThieleDistillation.mw Flowrate Between Two Tanks Assisted by a Pump View 54_FlowBetweenTwoTanks.mw on MapleNET or Download 54_FlowBetweenTwoTanks.mw

Hi all, Using maple 10 classic version, I am working with the below function of f(x): restart;fx:=cos(x)+2*sin(x);plot(fx,x=0..2*Pi,y=-3..3); I would like maple to show the x-axis values as radian instead of 0 to 6. How do I do this? If I now differenciate fx and find the value of zero I get the answer of arctan(2) fmx:=diff(fx,x);solve(fmx=0,x); Now I would like to visualise this by plotting a line from x=arctan(2) vertically to function f(x). How do I do this?? The maths is in place, its just getting maple to do what I want it to that creates problems ;-) Thanks in advance for any help.

Maple 9.52 outputs 0 to the expression, specified in the title:

> int(Dirac(x)*Heaviside(x+c), x=a..b);
0

while the answer I expect should be: Heaviside(c) if 0 belongs to [a..b], and 0 if [a..b] does not contain 0. In other words, it should be Heaviside(c)*(Heaviside(b)-Heaviside(a)).

Is my expectation correct? If it is, how to force Maple to provide the correct output?

Thanks in advance,
Anton Travleev.

One of my students was surprised at what happened after this command: > plot([sign(x), 'sign(x)' ],x=-1..1,color=[green,red]); I was too. One would expect to see an overlay of the green and red graphs. You don't. Curious. Jim Herod

Maplesoft just announced that a new version of Maple has been released that works on Intel based Macs. You can get full information on how to download this update on the Maple 10.04 download page The full press release is found below:

suppose you have the following equation a+bx=3+4x is there a way to have Maple compare the coefficients and come up with the a=3 and b=4 solutions? thanks

Hello everyone, I have written a procedure that makes some calculations for me, which I am calling repeatedly using a simple for loop. Basically what I am doing is using the for loop to change one of the several input parameters to the procedure and then use the result. Here is a quick example: > transmission0:=Matrix(1200,2): reflection0:=Matrix(1200,2): > for m from 1 to 1200 do > freq:=0.0416666666*m: > rcwa(31,0.0,0.2998/freq,6.0e-3,1.0,2234.950223+2237.186291*I,2.042123126+0.1633593958e-1*I,2234.950223+2237.186291*I,1.0,0.8333,18.0e-6,356.0e-6,18.0e-6): > transmission0[m,1]:=freq: >transmission0[m,2]:=te[M+1]:

I tried to solve this eigen value problem. I have a complex trigonometric function, whose graph looks similar to a tan function curve. I cannot use fsolve to solve for all the solutions at once, since the function has jump discontinuities. I am able to plot the function for small ranges and then from the plot, I use the fsolve command to determine my range of solution. Is there a way I can automate this process, meaning, can I write a program wherein I can get all the roots of the functions (w/o the jump discont. being shown as a root)at one go. Any help would be appreciated. Thanks

I am using a thir-party package made for Maple called HPC-Grid which enables parallel distribution of Maple programs over several porcessors. I wonder if anyone has any experiece using HPC-Grid. I am having problem with distributing global variables over the computing nodes. Can someone give me a hint on how to do it? Thanks

Maplesoft is providing an advance notice of changes to platform and operating system availability in the next major release of the Maple product family. Our current plans are to discontinue support for the IBM AIX, HP-UX, HP TRU64 , and SGI IRIX platforms and the Windows 98, ME and NT operating systems. Please see www.maplesoft.com/futureplatforms.aspx for full details.

Maple shuts down when a 3d plot is left clicked. It produces an error log file which says: An unexpected exception has been detected in native code outside the VM. Unexpected Signal : EXCEPTION_ACCESS_VIOLATION (0xc0000005) occurred at PC=0x692287D5 Function=atiPPHSN+0x187535 Library=C:\WINDOWS\system32\atioglxx.dll My ATI video cards are both (there seem to be both a primary and secondary) RADEON X800 XT Driver: ati2mtag.sys Wednesday, August 25, 2004 I'm not sure if I've done a 3d plot on this machine since I installed Maple 10 (and since updated to 10.03). But this has never happened before.

hi , can anyone tell me what's wrong with my codes ?? THANK YOU > restart: > with(LinearAlgebra): > A:=Matrix(2,2,[[100,600],[200,400]]); [100 600] A := [ ] [200 400] > list2:='list2': > list1:=list1: > n1[0]:=200: n2[0]:=200: list1[1]:=[0,n1[0]]: > for k from 1 to 1000 do > alpha[k]:=n1[k-1]*(100*n1[k-1]+600*n2[k-1]); > beta[k]:=n1[k-1]*(n1[k-1]+n2[k-1]); > gammas[k]:=(n2[k-1]*(200*n1[k-1]+400*n2[k-1]))/(n1[k-1]+n2[k-1]); > five[k]:=n2[k-1]*(n1[k-1]+n2[k-1]); > alphahat[k]:=(alpha[k])/(alpha[k]+beta[k]+gammas[k]+five[k]);