I now got where I made the mistake. I supposed not to have considered d = b^2/(1+b) but rather d=0, then I would get the quintic and subsequently the roots. I have now gotten all the roots as expected. Anyway thanks. Ib

Dear respected members, I want to find the roots of the following transcendental equation (which after rearrangement tranformed into a quintic) f(l, b, e, d) = b(s - m - g) - 1 + (1+b)(bm +1+l)exp(-d (l/bg + s/g -1))/((1+l)^2 + b) = 0 where s = (1+sqrt( 1+4(e+l)/b ) )/2 g = (1+sqrt( 1+4e/b ) )/2 m = (1-sqrt( 1+4l/b ) )/2 d = b^2/(1+b) by setting e = 0 and finding l in terms of b. The expected roots are l =0, -1+ i sqrt(b), -1- i sqrt(b), ( -6b +1+ sqrt(-32b^3+36b^2-12b+1) )/8b and sqrt( -6b +1- (-32b^3+36b^2-12b+1) )/8b. NB: The original message can be found at href='http://www.mapleprimes.com/files/4961_transcedental_eqtn.pdf'>Download 4961_transcedental_eqtn.pdf
View file details Thanks in anticipation of your responses Ib