paulmcquad

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These are replies submitted by paulmcquad

Hi,

Thanks in Advance.
I get this output ->

EvalSum := proc (S::(Sum(algebraic, name = range(integer)))) local i, k, x; i := op([2, 1], S); x := op(1, S); Typesetting:-mrow(InertForm:-Display(S, inert = false), Typesetting:-mo("="), (`@`(InertForm:-Typeset, `%+`))(seq(subs(i = Typesetting:-mn(sprintf("%d", k)), x), k = op([2, 2], S))), Typesetting:-mo("="), InertForm:-Typeset(value(S))) end proc; EvalSum(Sum(1/(k+7), k = -2 .. 3))

Sum(1/(k+7), k = -2 .. 3) = `%+`(1/5, 1/6, 1/7, 1/8, 1/9, 1/10) and `%+`(1/5, 1/6, 1/7, 1/8, 1/9, 1/10) = 2131/2520; "_noterminate"

(1)

NULL

But i would like this ->

Download ex2sigma.mw

I would like to see the distance between the 2 points on the graph. Here is an example see right photo.

Thanks in advance.

@dharr 

@acer Your procedure works perfectly. Thanks for your help.

I Found the Symbol. Its called a "Bar Over"

It's in the "Accents Palette > Bar Over"

I solved it myself. I didn't put in the right information.

plot(cos(t), t = -2*Pi .. 2*Pi)

plot(sin(t), t = 0 .. 4*Pi)

plot(cos(t), t = -2*Pi .. 2*Pi)

 

 

plot(sin(t), t = 0 .. 4*Pi)

 

 

``


 

Download Graph-cos.mw

Thanks for the info.

Got it working.

@Kitonum I see. I guess a like things to work out of the box. Not many newbies know to text based way.

@Carl Love Thanks for the info.

Example 7: Equations of Perpendicular Lines

 

``y = -(3/2)*x+2

 

2*x-3*y = 5; "_noterminate"

2, -1; "_noterminate"and m = 2/3; "_noterminate"

y = -5/3+(2/3)*x

(1)

 

``

``


 

Download Ch1_2_Lines_Exam7.mw

@Kitonum Thanks you made it look easy.

@acer I think you mean.

s1 := 1480.0;

Other than that thanks a million.

Thanks that worked. You're the best.

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