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robin1234

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Thanks and how?...

robin1234 5
May 26 2016
0 0

@vv Thanks, really. Can you briefly explain what you have done, since I have to run this for several differential equations? There is a parameter which I have to consider in my analysis, in the case posted above the value of that parameter was 2.

Dear all, thank you for replies. The pro...

robin1234 5
May 26 2016
0 1

Dear all,

thank you for replies. The problem is from economics, auction theory. I'm 101% sure of the boundary conditions, but unfortunately I have made a very stupid mistake in writing down the ODE. I really cannot imagine how I did not get it before.

Here the correct version. I still get back the same error message. I will try to work out the idea of solving the problem in b=3/8 to guess a solution.


NULL

deq1 := 1/(b-f(b)) = (2*(3-(1-f(b))*(diff(f(b), b, b))/((diff(f(b), b))*(diff(f(b), b)))))/(1-2*(b-(1-f(b))/(diff(f(b), b))))

1/(b-f(b)) = 2*(3-(1-f(b))*(diff(diff(f(b), b), b))/(diff(f(b), b))^2)/(1-2*b+2*(1-f(b))/(diff(f(b), b)))

 (1)

ic1 := eval(f(b), b = 3/8) = 0, eval(f(b), b = 1/2) = 1/2

f(3/8) = 0, f(1/2) = 1/2

 (2)

``

3

 (3)

dsol1 := dsolve({deq1, ic1}, method = bvp[middefer], numeric, range = 3/8 .. 1/2)

Error, (in dsolve/numeric/bvp) Newton iteration is not converging

  

NULL


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