tsunamiBTP

3 years, 157 days


These are answers submitted by tsunamiBTP

http://fourier.eng.hmc.edu/e102/lectures/Laplace_Transform/node1.html

Why MAPLE does not seem to cooperate I will need to experiment further.

I think I answered my own ??'s

December 30 2010 by tsunamiBTP 177

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I experimented with known functions with known transforms & what I proposed does not seem to work.

What I do not understand is the practice of employing the LaPlace transform to remove the time deriv's from anything other that an ORDINARY diff eq.  I have seen it done at least in practice of elasticity.  In electromagnetism they primarily stick with the fourier transform since they presume the signal is periodic in time.

 

If anyone...

1 further comment

December 30 2010 by tsunamiBTP 177

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Examination of the Bromwich integral vs invfourier they appear identical except the Bromwich integral contains a Re component in its integration bounds; whereas, the Re part for the invFourier = 0.

The logic seems to support the approach I mentioned earlier.

 

Another possibility, but is it valid?

Decompose s-->express it in polar form which gives an exponential with a Re exponent * expontial with an Im exponent.  The invlaplace exists for both so then convolve them to get the proper answer?

I have no reference basis for this to test if this approach is valid, but it does give an answer.

 

appreciate any counsel!!

See attached.

I decomposed s into its Re & Im components & expressed that in polar form & then took the inverse.  MAPLE gave an answer but is this VALID?

If I do this decomposition instead of taking the inverse LaPlace should I simply do the inverse Fourier instead & multiply the result by exp(Re(s)*t)?

Does this yield a proper result for the time domain given the original governing eq for F posed in the 1st posting?

 

inverse laplace transform

December 29 2010 by tsunamiBTP 177

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1 more thought:

The Fourier transform obviously works because you simply substitue e^jwt in for T & that divides out, but again that biases my temporal solution.  So I attempted what I have seen for solutions in longitudinal & shear wave problems in elastic media.

I suppose if there is another integral transform that would not bias my solution I could try that.  I'll do some experimenting or try to find some literature on what others may have attempted.

inverse laplace transform

December 29 2010 by tsunamiBTP 177

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Actually if you inspect the ratio within the sq root sign you see for the extreme cases for the denominator for very small s where the unity term dominates the inverse would exist & vice versa for very large s it does as well.  I played with it by simply removing terms from the denom.  So there must be some approach to handloe cases for intermediate s values?

inverse laplace transform

December 29 2010 by tsunamiBTP 177

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Not really, but I have seen people employ the LaPlace transform in wave problems for elasticity to remove the time derivatives & solve for the spatial distribution & then invert back to the time domain.  But I think they employ the Bromwich integral.  I simply tried to use invlaplace or Cauchy residues to get the job done, but that does not work either,

I did not want to use the Fourier transform because I thought that biases my solutions to be of periodic form.

I guess I need to familiarize myself with pdsolve & its output format if I am going to continue working problems like this!!!!!

Your output I can interpret.

I sometimes have difficulty with interpreting MAPLE output, but my result does not appear anything like yours.  Maybe it is telling me the same thing, but am I in some ODD display mode that causes MAPLE to display the answer as it is below or is it indeed giving me something different from yours?

Look at pdsolve(Q2), I think I put in the correct equation since I copied it from your posting?

 



nonlinear equation

December 25 2010 by tsunamiBTP 177

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Robert,

OK, I agree the eq is nonlinear, but what if I need to consider that term of the gradient magnitude.  Would it be more appropriate to move the LaPlacian & the zeroth order term of X to the other side of the eq & square it to get rid of the sq root?  Then you have a Helmholtz eq that is squared & you pick a value for the gradient that is considered a nominal value for the gradient magnitude for a defined region.

Then the Helmholtz...

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